C library functions - ispunct ()

C standard library - <ctype.h>

description

Whether the C library functionint ispunct (int c) Check the transmission characters are punctuation characters.Punctuation character may be a non-alphanumeric (same as in isalnum) Any graphic characters (as isgraph the same).

statement

Here is () statement ispunct function.

int ispunct(int c);

parameter

• c - This was a test of character.

return value

If c is a punctuation character, the function returns a nonzero value (true), otherwise it returns 0 (false).

Examples

The following example demonstrates ispunct () function is used.

#include <stdio.h>
#include <ctype.h>

int main()
{
   int var1 = 't';
   int var2 = '1';
   int var3 = '/';
   int var4 = ' ';

   if( ispunct(var1) )
   {
       printf("var1 = |%c| 是标点符号字符\n", var1 );
   }
   else
   {
       printf("var1 = |%c| 不是标点符号字符\n", var1 );
   }
   if( ispunct(var2) )
   {
       printf("var2 = |%c| 是标点符号字符\n", var2 );
   }
   else
   {
       printf("var2 = |%c| 不是标点符号字符\n", var2 );
   }
   if( ispunct(var3) )
   {
       printf("var3 = |%c| 是标点符号字符\n", var3 );
   }
   else
   {
       printf("var3 = |%c| 不是标点符号字符\n", var3 );
   }
   if( ispunct(var4) )
   {
       printf("var4 = |%c| 是标点符号字符\n", var4 );
   }
   else
   {
       printf("var4 = |%c| 不是标点符号字符\n", var4 );
   }
   
   return(0);
}  

Let's compile and run the above program, which will result in the following:

var1 = |t| 不是标点符号字符
var2 = |1| 不是标点符号字符
var3 = |/| 是标点符号字符
var4 = | | 不是标点符号字符

C standard library - <ctype.h>