C Exercise Example 81
100 cases of classic C language
Title: 809 * 800 * ?? = ?? double-digit + 9 + 1 * ?? ?? which represented 8 * ?? result of double-digit, 9 * ?? results 3 digits. ?? Representatives seeking double-digit, and the results after 809 * ??.
Program Analysis: None.
Source Code:
// Created by www.w3big.com on 15/11/9.
// Copyright © 2015年 本教程. All rights reserved.
//
#include<stdio.h>
#include<stdlib.h>
int main()
{
int i;
for(i=10;i<100;i++)
if(8*i<100&&9*i>99&&9*i<1000)
{
printf("??代表的两位数为：%d\n",i);
break;
}
printf("809*%d==800*%d+9*%d+1\n",i,i,i);
return 0;
}
Run the above example output is:
??代表的两位数为：12 809*12==800*12+9*12+1