C Exercise Example 4
100 cases of classic C language
Title: Enter a year on a certain day, judgment day is the day of the year?
Program analysis: March 5, for example, should be put before the two months together, then add five days or the first few days of this year, special circumstances, leap year and the input of more than 3 months to pay more to consider when one day .
Source Code:
#include <stdio.h>
int main()
{
int day,month,year,sum,leap;
printf("\n请输入年、月、日，格式为：年,月,日（2015,12,10）\n");
scanf("%d,%d,%d",&year,&month,&day); // 格式为：2015,12,10
switch(month) // 先计算某月以前月份的总天数
{
case 1:sum=0;break;
case 2:sum=31;break;
case 3:sum=59;break;
case 4:sum=90;break;
case 5:sum=120;break;
case 6:sum=151;break;
case 7:sum=181;break;
case 8:sum=212;break;
case 9:sum=243;break;
case 10:sum=273;break;
case 11:sum=304;break;
case 12:sum=334;break;
default:printf("data error");break;
}
sum=sum+day; // 再加上某天的天数
if(year%400==0||(year%4==0&&year%100!=0)) {// 判断是不是闰年
leap=1;
} else {
leap=0;
}
if(leap==1&&month>2) { // *如果是闰年且月份大于2,总天数应该加一天
sum++;
}
printf("这是这一年的第 %d 天。",sum);
printf("\n");
}
The above example output is:
请输入年、月、日，格式为：年,月,日（2015,12,10） 2015,10,1 这是这一年的第 274 天。