C Exercise Example 17

100 cases of classic C language

Title: Enter a line of characters, respectively, the statistics which the number of English letters, spaces, numbers and other characters.

Analysis Program: Using the while statement, the condition is not input character '\ n'.

Source Code:

//  Created by www.w3big.com on 15/11/9.
//  Copyright © 2015年 本教程. All rights reserved.
//

#include<stdio.h>
int main()
{
    char c;
    int letters=0,spaces=0,digits=0,others=0;
    printf("请输入一些字母：\n");
    while((c=getchar())!='\n')
    {
        if((c>='a'&&c<='z')||(c>='A'&&c<='Z'))
            letters++;
        else if(c>='0'&&c<='9')
            digits++;
        else if(c==' ')
            spaces++;
        else
            others++;
    }
    printf("字母=%d,数字=%d,空格=%d,其他=%d\n",letters,digits,spaces,others);
    return 0;
}

The above example output is:

请输入一些字母：
www.w3big.com 123
字母=12,数字=3,空格=1,其他=2

100 cases of classic C language